The derivative of 1/x^{2} is equal to -2/x^{3}. Note that 1/x^{2} is an algebraic function. In this article, we will learn how to find the derivative of 1 divided by x^{2} using the power rule, product rule, and the definition of derivatives.

## Derivative of 1/x^{2} Formula

The derivative of 1/x^{2} can be expressed as d/dx(1/x^{2}) or (1/x^{2})$’$. The derivative formula of 1 divided by x square is given below:

d/dx(1/x^{2}) = -2/x^{3} **or** (1/x^{2})$’$ = -2/x^{3}.

## What is the Derivative of 1/x^{2}?

Derivative of 1/x^{2} by power rule: Let us first find the derivative of 1 by x^{2} by the power rule of derivatives. Recall the power rule of derivatives: d/dx(x^{n}) = nx^{n-1}.

Follow the below steps to find the differentiation of 1 divided by x^{2}.

Express 1/x^{2} as a power of x | 1/x^{2} = x^{-2} |

Differentiate both sides w.r.t. x | d/dx(1/x^{2}) = d/dx(x^{-2}) |

Apply the power rule of derivatives | d/dx(1/x^{2}) = d/dx(x^{-2}) = -2x^{-2-1} |

Simplify | ∴ d/dx(1/x^{2}) = -2x^{-3} = -2/x^{3} |

Conclusion: | The derivative of 1/x^{2} is -2/x^{3}. |

## Derivative of 1/x^{2} by First Principle

If f(x) is a function of real variable x, then the derivative of f(x) by the first principle is given by the following limit formula:

$\dfrac{d}{dx}(f(x))$ $=\lim\limits_{h \to 0}\dfrac{f(x+h)-f(x)}{h}$

Put f(x) = 1/x^{2}

So the derivative of 1/x^{2} from first principle is

$\dfrac{d}{dx}\big(\dfrac{1}{x^2} \big)$ $=\lim\limits_{h \to 0}\dfrac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

= $\lim\limits_{h \to 0} \dfrac{x^2-(x+h)^2}{hx^2(x+h)^2}$

= $\lim\limits_{h \to 0} \dfrac{x^2-(x^2+2xh+h^2)}{hx^2(x+h)^2}$

= $\lim\limits_{h \to 0} \dfrac{-h(2x+h)}{hx^2(x+h)^2}$

= $\lim\limits_{h \to 0} \dfrac{-(2x+h)}{x^2(x+h)^2}$

= $\dfrac{-(2x+0)}{x^2(x+0)^2}$

= $\dfrac{-2x}{x^4}$ = $-\dfrac{2}{x^3}$.

Thus, the derivative of 1/x^{2} is equal to -2/x^{3} and this is obtained from the first principle of derivatives.

**Also Read:**

Derivative of 1/x: | -1/x^{2} |

Derivative of tan x: | sec^{2}x |

Derivative of e :^{sin x} | cos x e^{sin x} |

Derivative of log 2x: | 1/x |

## Derivative of 1/x^{2} by Product Rule

Now, we will find the derivative of 1/x^{2} by the substitution method together with the product rule of derivatives. For this let us put

z=1/x^{2}. We need to find dz/dx.

This implies that

zx^{2}=1

Differentiating with respect to x, we get that

$\dfrac{d}{dx}(zx^2)=\dfrac{d}{dx}(1)$

⇒ $z\dfrac{d}{dx}(x^2)+x^2\dfrac{d}{dx}(z)=0$ (by the product rule of derivatives)

⇒ $z\cdot 2x+x^2\dfrac{dz}{dx}=0$

⇒ $x^2\dfrac{dz}{dx}=-2zx$

⇒ $\dfrac{dz}{dx}=-\dfrac{2z}{x}$

⇒ $\dfrac{dz}{dx}=-\dfrac{2}{x^3}$ as z=1/x^{2}

So we have obtained the differentiation of 1/x^{2} which is -2/x^{3}.

## FAQs on Derivative of 1/x^{2}

**Q1: What is the derivative of 1/x**

^{2}?Answer: The derivative of 1/x^{2} is -2/x^{3}.

**Q2: What is the derivative of x**

^{2}?Answer: The derivative of x^{2} is 2x.