The divisors of 18 are those numbers that completely divide 18 without a remainder. In this section, we will discuss about divisors of 18.

- Divisors of 18: 1, 2, 3, 6, 9 and 18
- Negative divisors of 18: -1, -2, -3, -6, -9 and -18
- Prime divisors of 18: 2 and 3
- Number of divisors of 18: 6
- Sum of divisors of 18: 39
- Product of divisors of 18: 18
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## What are Divisors of 18

A number n is a divisor of 18 if $\frac{18}{n}$ is an integer. Note that if 18/n=m is an integer, then both m and n will be the divisors of 18.

To find the divisors of 18, we need to find the numbers n such that 18/n becomes an integer. We have:

18/1=18 | 1, 18 are divisors of 18. |

18/2=9 | 2, 9 are divisors of 18 |

18/3=6 | 3, 6 are divisors of 18 |

No numbers other than 1, 2, 3, 6, 9 and 18 can divide 18. So we conclude that

The divisors of 18 are: 1, 2, 3, 6, 9 and 18. |

Thus, the total number of divisors of 18 is six.

## Negative Divisors of 18

We know that if m is a divisor of a number, then -m is also a divisor of that number.

As the divisors of 18 are 1, 2, 3, 6, 9, and 18, we can say that:

The negative divisors of 18 are -1, -2, -3, -6, -9, and –18.

## Prime Divisors of 18

The divisors of 18 are 1, 2, 3, 6, 9, and 18. Among these numbers, only 2 and 3 are prime numbers. So we obtain that:

The prime divisors of 18 are 2 and 3.

## Sum, Product, Number of Divisors of 18:

The prime factorization of 18 is given below.

18 = 2^{1 }× 3^{2}

(i) By the number of divisors formula, we have that the number of divisors of 18 is

=(1+1)(2+1)=2×3=6.

(ii) By the sum of divisors formula, we have that the sum of the divisors of 18 is

$=\dfrac{2^2-1}{2-1} \times \dfrac{3^3-1}{3-1}$

$=\dfrac{4-1}{1} \times \dfrac{27-1}{2}$

$=3 \times 13=39$

(iii) By the product of divisors formula, we have that the product of the divisors of 18 is

=18^{(Number of divisors of 18)/2}

=18^{6/2}

=18^{3}

Video solution of Divisors of 18:

## Questions and Answers about Divisors of 18

**Q1:** Find the greatest common divisor of 18 and 24.

**Solution:**

We know that the divisors of 18 are 1, 2, 3, 6, 9, and 18. Also, the divisors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24.

So the common divisors of 18 and 24 are 1, 2, 3, and 6.

Thus, the greatest common divisor of 18 and 24 is 6.

**Q2:** Find the set H={x: x is a divisor of 18}.

**Solution:**

The set H contains the divisors of 18, and we know that the divisors of 18 are 1, 2, 3, 6, 9, and 18.

Thus the set

H={1, 2, 3, 6, 9, 18}.

**Q3:** Is 6 a divisor of 18?

**Solution:**

We know that 18/6=3, that is, 18 is divisible by 6 completely with the remainder 0. Thus, 6 is a divisor of 18.

**Q4:** Is 18 a divisor of 6?

**Solution:**

No, 18 is not a divisor of 6 as we know that divisor cannot be greater than dividend.

**Related Topics:**

## FAQs on Divisors of 18

**Q1: Find the divisors of 18.**

Ans: The divisors of 18 are 1, 2, 3, 6, 9, and 18.

**Q2: What are the prime divisors of 18?**

Ans: 2 and 3 are the prime divisors of 18.

**Q3: Find the sum of the divisors of 18.**

Ans: The sum of the divisors of 18 is $=\frac{2^2-1}{2-1} \times \frac{3^3-1}{3-1}$=39.