Divisors of 56 - Mathstoon

The divisors of 56 are those numbers that completely divide 56 with the remainder zero. In this section, we will discuss about divisors of 56.

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Highlights of Divisors of 56

A number n is a divisor of 56 if $\dfrac{56}{n}$ is an integer. Note that if 56/n=m is an integer, then both m and n will be the divisors of 56.

To find the divisors of 56, we need to find the numbers n such that 56/n becomes an integer. We have:

No numbers other than 1, 2, 4, 7, 8, 14, 28, and 56 can divide 56. So we conclude that

The divisors of 56 are:

1, 2, 4, 7, 8, 14, 28, and 56.

Thus, the total number of divisors of 56 is eight.

We know that if m is a divisor of a number, then -m is also a divisor of that number.

As the divisors of 56 are 1, 2, 4, 7, 8, 14, 28, and 56, we can say that:

The negative divisors of 56 are -1, -2, -4, -7, -8, -14, -28, and -56.

The divisors of 56 are 1, 2, 4, 7, 8, 14, 28, and 56. Among these numbers, only 2 and 7 are prime numbers. So we obtain that:

The prime divisors of 56 are 2 and 7.

Video solution of Divisors of 56:

The prime factorization of 56 is given below.

56 = 2³ × 7¹

(i) By the number of divisors formula, we have that the number of divisors of 56 is

=(3+1)(1+1)=4×2=8.

(ii) By the sum of divisors formula, we have that the sum of the divisors of 56 is

$=\dfrac{2^4-1}{2-1} \times \dfrac{7^2-1}{7-1}$

$=\dfrac{16-1}{1} \times \dfrac{49-1}{6}$

$=15 \times 8=120$

(iii) By the product of divisors formula, we have that the product of the divisors of 56 is

=56^{(Number of divisors of 56)/2}

=56^8/2

=56⁴

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