Multiples of 9

The multiples of 9 are obtained by multiplying integers with 9. In this section, we will learn about the multiples of 9. For more details about multiples, see our page “Multiples of a Number“.

What are Multiples of 9?

A number is called a multiple of 9 if it is completely divisible by 9 with the remainder zero.

For example, 9 divides 18 completely, so by the definition 18 is a multiple of 9. Similarly, 9, 18, 27, 36, 90, 900, etc. are all examples of multiples of 9 as they are completely divisible 9.

Remark: From the above definition, it is clear that any multiple of 9 can be written as 9n for some integer n. So the set of multiples of 9 is given by

{9n: n is an integer}

First 10 Multiples of 9

The first 10 multiples of 9 are as follows:

9×1=99×2=18
9×3=279×4=36
9×5=459×6=54
9×7=639×8=72
9×9=819×10=90

So we have:

The first 10 multiples of 9 are

9, 18, 27, 36, 45, 54, 63, 72, 81 and 90.

Also Read:

Question: What are the first ten multiples of 9?

Video Solution:

First 20 Multiples of 9

The first 20 multiples of 9 are given below:

9×1=99×2=18
9×3=279×4=36
9×5=459×6=54
9×7=639×8=72
9×9=819×10=90
9×11=999×12=108
9×13=1179×14=126
9×15=1359×16=144
9×17=1539×18=162
9×19=1719×20=180

So we have:

The first 20 multiples of 9 are

9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108, 117, 126, 135, 144, 153, 162, 171, and 180.

FAQs on Multiples of 9

Q1: Write first five multiples of 9.

Answer: The first five multiples of 9 are 9, 18, 27, 36, and 45.

Q2: What is the sum of first five multiples of 9?

Answer: The sum of the first five multiples of 9 is 9+18+27+36+45 = 135.

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