SN Dey class 11 solutions | Trigonometric ratios of compound angles long answer type questions SN Dey class 11 solutions | Compound angles SN Dey Solution | Compound angles long answer type questions solutions | S N Dey Class 11 Compound Angles Solutions | WB math class 11 solution
Ex 1: Prove that $\tan(A+B)-\tan(A-B)=\frac{\sin 2B}{\cos^2B-\sin^2A}$
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Ex 2: If $\tan \beta = \frac{n\sin\alpha \cos\alpha}{1-n\sin^2\alpha},$ Show that, tan(α-β) = (1-n) tan α.
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Ex 3: If m tan(θ-30°) = n tan(θ+120°), show that, 2 cos2θ = $\frac{m+n}{m-n}$.
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Ex 4: If cos(β-γ) + cos(γ-α) + cos(α-β) = $-\frac{3}{2}$, show that, cosα + cosβ + cosγ=0 and sinα + sinβ + sinγ=0. Hence deduce that
cos(β-γ) = cos(γ-α) = cos(α-β) = $-\frac{1}{2}$.
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Ex 5: If α ≠ β and a tanα + b tanβ = (a+b) tan $\frac{\alpha+\beta}{2}$, show that, $\frac{\cos \alpha}{\cos \beta}=\frac{a}{b}$.
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Ex 6: If sinθ=k sin(θ+φ), show that, tan(θ+φ)=$\frac{\sin \phi}{\cos \phi -k}$.
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Ex 7: If $\frac{\cot(\alpha-\beta)}{\cot \alpha}$+$\frac{\cos^2 \gamma}{\cos^2 \alpha}=1$, show that, tan2γ + tanα cotβ =0.
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Ex 8: If tanθ=$\frac{x \sin \alpha+y\sin \beta}{x \cos \alpha+y\cos \beta}$, prove that, x sin(θ-α) + y sin(θ-β) =0.
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