On this page, we will learn about the third isomorphism theorem for groups along with its statement and proof.
Table of Contents
Third Isomorphism Theorem Statement
Let G be a group and H, K be its two normal subgroups such that H ≤ K. Then we have a group isomorphism
(G/H)/(K/H) ≅ G/K.
Third Isomorphism Theorem Proof
First, we prove that K/H is a normal subgroup of G/H. For gH∈ G/H and kH ∈ K/H, we have that
gH kH (gH)-1
= gH kH g-1 H
= gkg-1 H
∈ K/H as gkg-1∈K. This is because K is normal in G.
This shows that K/H is normal in G/H.
Next, we prove the group isomorphism. Let us define a mapping
φ: G/H → G/K
by φ(gH) = gK for g ∈ G.
Let us show that φ is well-defined. For g1, g2∈G with g1H=g2H, we have that
g1 = g2h for some element h∈H.
As H ≤ K, we have h∈K. Thus, we can conclude that
g1K=g2K
⇒ φ(g1H) = φ(g2H).
This shows that φ is well-defined.
By definition, φ is onto.
Now, Ker φ = {gH∈ G/H: φ(gH) = K}
= {gH∈ G/H: gK = K}
= {gH∈ G/H: g ∈ K}
= G/K.
Hence, by the first isomorphism theorem of groups, we obtain that
$\dfrac{G/H}{K/H} \cong G/K$.
This completes the proof of the third isomorphism theorem for groups.
For Other Isomorphism Theorems Click Below:
Also Read:
Group Theory: The basics of group theory are discussed here. Order of a Group: The order of a group and its elements are discussed here with formulas. Abelian Group: The definition of an abelian group is discussed along with its properties and examples Center of a Group Orbit Stabilizer Theorem: Its statement and proof are provided here. Cyclic Group: The definition, properties, and related theorems on cyclic groups are discussed. Kernel of a Group Homomorphism Group Homomorphism Order of a Permutation: How to Find |
FAQs
Answer: Let G be a group. Let H, K be two normal subgroups of G. If H ≤ K, then we have a group isomorphism (G/H)/(K/H) ≅ G/K.
This article is written by Dr. T. Mandal, Ph.D in Mathematics. On Mathstoon.com you will find Maths from very basic level to advanced level. Thanks for visiting.